Hexadecimal to Binary Conversion in C
To convert hexadecimal number to binary number in C programming, you have to ask to the user to enter the hexadecimal number to convert it
into binary number to display the equivalent value in binary
C Programming Code to Convert Hexadecimal to Binary
Following C program ask to the user to enter any number in hexadecimal to convert it into binary, then display the result on the screen:
/* C Program - Hexadecimal to Binary Conversion */
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
long int i=0;
char binnum[100], hexdec[100];
printf("Enter any hexadecimal number : ");
scanf("%s",hexdec);
printf("\nEquivalent Binary value is : ");
while(hexdec[i])
{
switch(hexdec[i])
{
case '0' : printf("0000");
break;
case '1' : printf("0001");
break;
case '2' : printf("0010");
break;
case '3' : printf("0011");
break;
case '4' : printf("0100");
break;
case '5' : printf("0101");
break;
case '6' : printf("0110");
break;
case '7' : printf("0111");
break;
case '8' : printf("1000");
break;
case '9' : printf("1001");
break;
case 'A' : printf("1010");
break;
case 'B' : printf("1011");
break;
case 'C' : printf("1100");
break;
case 'D' : printf("1101");
break;
case 'E' : printf("1110");
break;
case 'F' : printf("1111");
break;
case 'a' : printf("1010");
break;
case 'b' : printf("1011");
break;
case 'c' : printf("1100");
break;
case 'd' : printf("1101");
break;
case 'e' : printf("1110");
break;
case 'f' : printf("1111");
break;
default : printf("\nInvalid hexadecimal digit %c",hexdec[i]);
}
i++;
}
getch();
}
When the above c program is compile and executed, it will produce the following result:
Same Program in Other Programming Language
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