C Program to Print Some Series upto N Term

Here we will learn about how to print some series upto the given term (by user at run-time). Here are the list of some programs that will ask from user to enter the value of N (where N is the limit or term upto which the series will be printed) to print the series upto that term.

C Print 1, 2, 3, 4... upto N Term

Here is the program that will print the series 1, 2, 3, 4... upto N term (given by user at run-time):

#include<stdio.h>
#include<conio.h>
int main()
{
    int N, i;
    printf("Enter the value of N (limit): ");
    scanf("%d", &N);
    printf("\n");
    for(i=1; i<=N; i++)
    {
        if(i==N)
            printf("%d", i);
        else
            printf("%d,", i);
    }
    getch();
    return 0;
}

As the above program was written under Code::Blocks IDE, here is the sample run after successful build and run. This is the first snapshot of the sample run:

c program print series

Now provide the limit say 25 to print the series upto the given term as shown here in the second snapshot of the sample run:

print series upto n term c

Here are some of the main steps used in above program:

  • Receive the value of N to print the series upto that given term
  • Create a for loop that runs from 1 to the given number that is N
  • Inside the loop print the value of i one by one

C Print 1, 4, 9, 16... upto N Term

Here is another program that will print the series 1, 4, 9, 16... upto N term. The value of N will be provided by user at run-time:

#include<stdio.h>
#include<conio.h>
int main()
{
    int N, i, inc=1, val=1, temp;
    printf("Enter the value of N (limit): ");
    scanf("%d", &N);
    printf("\n");
    for(i=1; i<=N; i++)
    {
        if(i>1)
        {
            inc = inc+2;
            temp = inc;
            val = val+temp;
        }
        if(i==N)
            printf("%d", val);
        else
            printf("%d, ", val);
    }
    getch();
    return 0;
}

Here is the final snapshot of the sample run of above program:

print series in c

Here are some of the main steps used in above program:

  • Receive the value of N say 10 as input to print the series upto that given term (10 times here)
  • Create a for loop that runs from 1 to N
  • Inside the for loop, check whether the loop variable i is greater than 1 or not
  • If it is, then increment a variable say inc by 2 each time and initialized it to the variable say temp. And finally add it with another variable say val and initialize it to the variable val which will be the current value to be printed as output
  • Never forgot to initialize 1 to both the variable say inc and val at start of the program
  • Therefore, at first run of the for loop, i holds 1 which is not greater than 1, therefore the program flow does not goes inside the if block, and the value of i will be printed directly
  • At second run, i holds 2, which is greater than 1, therefore the program flow goes inside the if block, and inc+2 or 1+2 or 3 will be initialized to inc, and inc or 3 will be initialized to temp, and val+temp or 1+3 or 4 will be initialized to val. Finally print the value of val which is 4
  • At third run, i holds 3, which is again greater than 1, therefore inside the if block, inc+2 or 3+2 or 5 will be initialized to inc, and inc or 5 will be initialized to temp, and val+temp or 4+5 or 9 will be initialized to val. Finally print the value of val and continue to check for the next value of i
  • In this way, the series gets printed as output

C Print 0, 2, 6, 12... upto N Term

Let's create another program that prints another series that is 0, 2, 6, 12... upto N term:

#include<stdio.h>
#include<conio.h>
int main()
{
    int N, temp, inc=0, val=0, i;
    printf("Enter the value of N (limit): ");
    scanf("%d", &N);
    for(i=1; i<=N; i++)
    {
        if(i>1)
        {
            inc = inc + 2;
            temp = inc;
            val = val + temp;
        }
        if(i==N)
            printf("%d", val);
        else
            printf("%d, ", val);
    }
    getch();
    return 0;
}

Here is the sample run of the above program:

print series in c program

Use the same steps to create the above program except that initialize 0 to both the variable say val and inc (in this program) in place of 1 as done in earlier program.

C Print 1, 8, 27, 64... upto N Term

Let's create another program to print another series that is 1, 8, 27, 64... upto N term:

#include<stdio.h>
#include<conio.h>
int main()
{
    int N, i, val;
    printf("Enter the value of N (limit): ");
    scanf("%d", &N);
    for(i=1; i<=N; i++)
    {
        val = i*i*i;
        if(i==N)
            printf("%d", val);
        else
            printf("%d, ", val);
    }
    getch();
    return 0;
}

This is the final snapshot of the sample run of above program:

print series c program

C Print 1, 2, 4, 7... upto N Term

Let's create one more program to print one more series that is 1, 2, 4, 7, 11, 16,... upto N term in C:

#include<stdio.h>
#include<conio.h>
int main()
{
    int N, i, val=1, temp, inc=1;
    printf("Enter the value of N (limit): ");
    scanf("%d", &N);
    for(i=1; i<=N; i++)
    {
        if(i>1)
        {
            val = val + inc;
            inc++;
        }
        if(i==N)
            printf("%d", val);
        else
            printf("%d, ", val);
    }
    getch();
    return 0;
}

This is the snapshot of the sample run:

printing series in c language

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