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In this tutorial, we will learn about how to create a program in C that can convert any given binary number by user (at run-time) into its equivalent hexadecimal value. At last we have also created same purpose function-driven program that also converts binary number to hexadecimal number.

But before going through the program, if you are not aware of

- Binary Number
- Hexadecimal Number
- Binary to Hexadecimal Conversion Process

then refer to Binary to Hexadecimal conversion step by step process. Now let's move on to the program.

The question is, **Write a program in C that converts binary number to hexadecimal**. The answer to this question
is:

// Binary to Hexadecimal in C // ----codescracker.com---- #include<stdio.h> #include<conio.h> int main() { int binnum, hex=0, mul=1, count=1, rem, i=0; char hexnum[20]; printf("Enter any Binary Number: "); scanf("%d", &binnum); while(binnum!=0) { rem = binnum%10; hex = hex + (rem*mul); if(count%4==0) { if(hex<10) hexnum[i] = hex+48; else hexnum[i] = hex+55; mul = 1; hex = 0; count = 1; i++; } else { mul = mul*2; count++; } binnum = binnum/10; } if(count!=1) hexnum[i] = hex+48; if(count==1) i--; printf("\nEquivalent Hexadecimal Value = "); for(i=i; i>=0; i--) printf("%c", hexnum[i]); getch(); return 0; }

As the above program was written under **Code::Blocks** IDE, therefore after successful build and run, you will get the following
output on your output screen. This is the first snapshot of the sample run:

Now supply any binary number say **1101110** and press ENTER key to see its equivalent hexadecimal value as shown in the
second snapshot of the sample run given below:

Here is the final snapshot of above program's another sample run:

- Receive any binary number from user at run-time say
**1101** - Create a while loop that runs until the value of given binary number becomes 0
- That is, at first run of the
**while**loop, the condition**binnum!=0**or**1101!=0**evaluates to be true, therefore program flow goes inside the loop - And
**binnum%10**or**1101%10**or**1**gets initialized to**rem**, then**hex + (rem*mul)**(we have initialized**hex**and**mul**with**0**and**1**at start of the program) or**0 + (1*1)**or**1**gets initialized to**hex** - Now we have created a if block in such way, that the value of
**hex**gets initialized to**hexnum[]**character array as hexadecimal digit one by one in corresponding to each 4-pair of binary digit. - Therefore, as at first run of the
**while**loop, the condition of**if**statement, that is**count%4==0**(we have initialized the variable**count**with 1 at start of the program) or**1%4==**evaluates to be false, therefore program flow goes inside the**else**block of**if**statement, and there**mul*2**or**1*2**or**2**gets initialized to**mul**, and the value of**count**variable gets incremented and becomes 2. - At last,
**binnum/10**or**1101/10**or**110**gets initialized to**binnum**, and then the program flow goes back to the condition of**while**loop - There again
**binnum!=0**or**110!=0**evaluates to be true, and the program flow again goes inside the**while**loop - And
**binnum%10**or**110%10**or**0**gets initialized to**rem**, then**hex + (rem*mul)**or**1 + (0*2)**or**1**gets initialized to**hex** - Now the condition of
**if**block, that is**count%4==0**or**2%4==**evaluates to be false, and the program flow goes inside the**else**block, and**mul*2**or**2*2**or**4**gets initialized to**mul**, and the value of**count**gets incremented and becomes 3 - At last,
**binnum/10**or**110/10**or**11**gets initialized to**binnum**, and then the program flow goes back to the condition of**while**loop - There again
**binnum!=0**or**11!=0**evaluates to be true, and the program flow again goes inside the**while**loop - And
**binnum%10**or**11%10**or**1**gets initialized to**rem**, then**hex + (rem*mul)**or**1 + (1*4)**or**5**gets initialized to**hex** - Now the condition of
**if**block, that is**count%4==0**or**3%4==**evaluates to be false, and the program flow goes inside the**else**block, and**mul*2**or**4*2**or**8**gets initialized to**mul**, and the value of**count**gets incremented and becomes 4 - At last,
**binnum/10**or**11/10**or**1**gets initialized to**binnum**, and then the program flow goes back to the condition of**while**loop - There again
**binnum!=0**or**1!=0**evaluates to be true, and the program flow again goes inside the**while**loop - And
**binnum%10**or**1%10**or**1**gets initialized to**rem**, then**hex + (rem*mul)**or**5 + (1*8)**or**13**gets initialized to**hex** - Now the condition of
**if**block that is**count%4==0**or**4%4==**evaluates to be true, therefore the program flow goes inside the**if**block this time, and as the value of**hex**(13) is not less than 10, therefore**hex+55**or**13+55**or**68**(68 is the ASCII code for C) gets initialized to**hexnum[i]**(we have initialized the variable**i**with 0 at start of the program) or**hexnum[0]**, and then 1, 0, and 1 gets initialized to**mul**,**hex**and**count**respectively. And the value of**i**gets incremented and becomes 1 - At last,
**binnum/10**or**1/10**or**0**gets initialized to**binnum**, and the program flow goes back to the condition of the**while**loop - There,
**binnum!=0**or**0!=0**evaluates to be false, and the program flow does not goes inside the loop this time, that is the program flow goes out from the loop or exits from the loop, and then the condition**count!=1**or**1!=1**evaluates to be false, therefore the program flow does not goes inside the**if**block. - Now the condition of the second
**if**block, that is**count==1**or**1==1**evaluates to be true, therefore the value of**i**gets decremented by 1, and becomes 0. - Now we have created the
**for**loop that runs from the current value of**i**to 0 - And print the value of each and every hexadecimal digit one by one, from last index to the first one
- Here we have used ASCII code for the number and characters, that is
**0, 1, 2, 3, ..., 7, 8, 9, A, B, C, D, E, F** - That is, the ASCII code for 0, 1, 2, ..., 8, 9 are
**48, 49, 50, ..., 56, 57**. And the ASCII code for**A, B, C, .., E, F**are**65, 66, 67, ..., 69, 70** - Therefore, if the value of
**hex**is 0, then 0+48 (the ASCII code of 0) gets initialized to**hexnum[]**, in same way if the value of**hex**is 13, then as 13 is greater than 10, therefore**13+55**or**68**(the ASCII code for C) gets initialized to**hexnum[]**

Here is another program using user-defined function named **BinToHex()**
that also does the same job, that is to convert any binary number to hexadecimal number.

Here, we have declared the variable **i** and the character array **hexnum[]** as global to make it known
in both the function, that is **main()** and **BinToHex()**.

// Binary to Hexadecimal in C using Function // ----codescracker.com---- #include<stdio.h> #include<conio.h> void BinToHex(int bin); int i=0; char hexnum[20]; int main() { int binnum; printf("Enter any Binary Number: "); scanf("%d", &binnum); BinToHex(binnum); printf("\nEquivalent Hexadecimal Value = "); for(i=i; i>=0; i--) printf("%c", hexnum[i]); getch(); return 0; } void BinToHex(int bin) { int hex=0, mul=1, count=1, rem; while(bin!=0) { rem = bin%10; hex = hex + (rem*mul); if(count%4==0) { if(hex<10) hexnum[i] = hex+48; else hexnum[i] = hex+55; mul = 1; hex = 0; count = 1; i++; } else { mul = mul*2; count++; } bin = bin/10; } if(count!=1) hexnum[i] = hex+48; if(count==1) i--; }

Here is the final snapshot of the above program's sample run:

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