In this article, you will learn and get code on hexadecimal to binary conversion in C++. But if you're not aware about simple steps and formula used for the conversion, then you can refer to hexadecimal to binary to get every required things.
To convert hexadecimal number to binary number in C++ programming, you have to ask from user user to enter the hexadecimal number first. And then convert it into its equivalent binary value and print the equivalent binary value as output.
You can create the program in two ways:
This program uses switch case to match and print binary equivalent of each and every hex digit.
// C++ Print Equivalent Binary Value of Hexadecimal
// ----codescracker.com----
#include<iostream>
using namespace std;
int main()
{
int i=0;
char hexDecNum[10];
cout<<"Enter the Hexadecimal Number: ";
cin>>hexDecNum;
cout<<"\nEquivalent Binary Value = ";
while(hexDecNum[i])
{
switch(hexDecNum[i])
{
case '0':
cout<<"0000";
break;
case '1':
cout<<"0001";
break;
case '2':
cout<<"0010";
break;
case '3':
cout<<"0011";
break;
case '4':
cout<<"0100";
break;
case '5':
cout<<"0101";
break;
case '6':
cout<<"0110";
break;
case '7':
cout<<"0111";
break;
case '8':
cout<<"1000";
break;
case '9':
cout<<"1001";
break;
case 'A':
case 'a':
cout<<"1010";
break;
case 'B':
case 'b':
cout<<"1011";
break;
case 'C':
case 'c':
cout<<"1100";
break;
case 'D':
case 'd':
cout<<"1101";
break;
case 'E':
case 'e':
cout<<"1110";
break;
case 'F':
case 'f':
cout<<"1111";
break;
default:
cout<<"--Invalid Hex Digit ("<<hexDecNum[i]<<")--";
}
i++;
}
cout<<endl;
return 0;
}
This program was build and run under Code::Blocks IDE. Here is its sample run:
Now supply hexadecimal number input say 2AD3 and press ENTER key to print its equivalent
binary value as shown in the output given below:
The dry run of above program with hexadecimal input say 2AD3 goes like:
In a case, if user enters an invalid hexadecimal digit. For example, if user enters hexadecimal input in following ways (containing one or more invalid hex digit, with or without valid ones):
In all the three cases, if the program (created above) found any hexadecimal digit (without caring where and how it presents), a message --Invalid Hex Digit (HexDigit)-- gets printed in a way that:
Here is the sample output for second case:
Note - Above program doesn't convert given hexadecimal number into its equivalent binary value. Rather it just prints the binary equivalent using switch case.
Now let's create another program that actually converts the number from hexadecimal to binary.
This program uses strcat() function to concatenate the binary equivalent of each and every hexadecimal digit (hex digit) one by one to a variable say binaryNum[]. And finally prints its value as output.
// C++ Program to Convert Hexadecimal to Binary
// ----codescracker.com----
#include<iostream>
#include<string.h>
using namespace std;
int main()
{
int i=0, chk=0;
char hexDecNum[10], binaryNum[40]="";
cout<<"Enter the Hexadecimal Number: ";
cin>>hexDecNum;
while(hexDecNum[i])
{
switch(hexDecNum[i])
{
case '0':
strcat(binaryNum, "0000");
break;
case '1':
strcat(binaryNum, "0001");
break;
case '2':
strcat(binaryNum, "0010");
break;
case '3':
strcat(binaryNum, "0011");
break;
case '4':
strcat(binaryNum, "0100");
break;
case '5':
strcat(binaryNum, "0101");
break;
case '6':
strcat(binaryNum, "0110");
break;
case '7':
strcat(binaryNum, "0111");
break;
case '8':
strcat(binaryNum, "1000");
break;
case '9':
strcat(binaryNum, "1001");
break;
case 'A':
case 'a':
strcat(binaryNum, "1010");
break;
case 'B':
case 'b':
strcat(binaryNum, "1011");
break;
case 'C':
case 'c':
strcat(binaryNum, "1100");
break;
case 'D':
case 'd':
strcat(binaryNum, "1101");
break;
case 'E':
case 'e':
strcat(binaryNum, "1110");
break;
case 'F':
case 'f':
strcat(binaryNum, "1111");
break;
default:
chk = 1;
break;
}
i++;
}
if(chk==0)
cout<<"\nEquivalent Binary Value: "<<binaryNum;
else
cout<<"\nInvalid Hexadecimal Digit";
cout<<endl;
return 0;
}
Here is its sample run with hexadecimal number input as AabB:
