In this article, you will learn and get code about finding HCF of n numbers. But before going through the program, I recomment you to visit Find HCF of Two Numbers once (if not visited). Because, the program given here is relatable to the program in that article.
Now let's create a program to find HCF of all the numbers given by user at run-time.
// ----codescracker.com----
#include<stdio.h>
#include<conio.h>
int main()
{
int arr[10], n, mp, i, count;
printf("Enter the Size: ");
scanf("%d", &n);
printf("Enter %d Numbers: ", n);
for(i=0; i<n; i++)
scanf("%d", &arr[i]);
i=0;
mp = arr[i];
while(i<n)
{
if(mp<arr[i])
mp = arr[i];
i++;
}
while(1)
{
i=0;
count=0;
while(i<n)
{
if(arr[i]%mp==0)
count++;
i++;
}
if(count==n)
break;
else
mp--;
}
printf("\nHCF(");
for(i=0; i<(n-1); i++)
printf("%d,", arr[i]);
printf("%d) = %d", arr[i], mp);
getch();
return 0;
}
This program was build and run under Code::Blocks IDE. Here is the sample run:
Now supply the size say 3 and enter any 3 numbers say 8, 9, 25. Press ENTER key to
see the following output:
Here is another sample run for 2 numbers:
This program is same as of previous program LCM of n Numbers in C. Except we have reverse the condition of if block from:
mp%arr[i]==0
to
arr[i]%mp==0
and the statement from:
mp++;
to
mp--;
Why these two is reversed is discussed in LCM & HCF of Two Numbers in C. The brief description is:
And as multiple of a number is greater than the number, whereas factor of a number is lower than the number. I hope you are gettting some idea about it. If not, then kindly visit:
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