- C Programming Examples
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- C Print Hello World
- C Get Input from User
- C Print Integer
- C Add Two Numbers
- C Add Subtract Multiply Divide
- C Add n Numbers
- C Area Perimeter of Square
- C Area Perimeter of Rectangle
- C Area Circum of Circle
- C Fahrenheit to Celsius
- C Celsius to Fahrenheit
- C Inches to Centimeters
- C Kilogram to Gram
- C Reverse a Number
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- C Interchange Numbers
- C Print ASCII Value
- C Print Fibonacci Series
- C Check Palindrome or Not
- C Check Armstrong or Not
- C Find Armstrong Numbers
- C Find nCr and nPr
- C Find Profit Loss
- C Sum of their Square
- C First & Last Digit Sum
- C Sum of All Digit
- C Product of All Digit
- C Print Total Digit in Number
- C Check Perfect Number
- C Find Basic Gross Salary
- C Round Number to Integer
- C Print Series upto n Term
- C Find Factors of Number
- C if-else & Loop Programs
- C Check Even or Odd
- C Check Prime or Not
- C Check Alphabet or Not
- C Check Vowel or Not
- C Check Leap Year or Not
- C Is Reverse Equal Original
- C Make Calculator
- C Add Digits of Number
- Count Positive Negative Zero
- C Largest of Two Numbers
- C Largest of Three Numbers
- C Smallest of Two Numbers
- C Smallest of Three Numbers
- C Find Factorial of Number
- C Find LCM & HCF
- C Find LCM of n Numbers
- C Find HCF of n Numbers
- C Find Arithmetic Mean
- C Find Average, Percentage
- C Find Student Grade
- C Print Table of Number
- C Print Prime Numbers
- C Find Discount Purchase
- C Calculate Parcel Charge
- C Calculate Wage of Labor
- C Print Phone Bill
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- C Sum/Product of Even/Odd
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- C Sum All Matrix Elements
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- C Tutorial

# C Program to Find and Print the Product of All Digits of Any Number

Here we will learn about how to create a program in C that will ask the user to enter any number (at run-time) as input and then calculate and print the product of all the digits of that given number. This program will only calculate the non-zero digit's product:

#include<stdio.h> #include<conio.h> int main() { int num, prod=1, rem; printf("Enter any number: "); scanf("%d", &num); while(num>0) { rem = num%10; if(rem!=0) prod = prod*rem; num = num/10; } printf("\nProduct of Digit = %d", prod); getch(); return 0; }

As the program was written in the Code::Blocks IDE, here is the output you will see on your screen after a successful build and run. Let's suppose that the user has supplied the input number as 2345 and pressed the ENTER key:

Let's take another sample run:

As you can see from the above sample run, 0 is skipped while multiplying the digits of the given number, as if we take 0 along with a non-zero digit, then the product will be 0.

Here are some of the main steps used in the above program:

- Receive any number as input.
- Create a while loop that runs until the number is greater than 0.
- Inside the for loop, divide the number by 10 to find the remainder, or last digit, of the given number.
- If the current remainder value is not equal to 0, multiply it by the prod variable and set it to the prod variable, which is the product of all the non-zero digits of a number.
- Never forget to give the variable prod the value 1 at the beginning of the program, in the main() function.
- After multiplying the remainder with prod, divide the number by 10 and continue to check and do the same operation.
- Let's suppose that the user has provided the number 247.
- At the first run of the while loop, num holds 247, which is greater than 0.
- The program flow then enters the while loop, where num%10 or 247%10 or 7 is initialized to the rem variable, which is not equal to 0. The program flow then enters the if block (present inside the while loop), where prod*rem or 1*7 or 7 is initialized to prod (prod initially holds 1), and num/10 or 247%10 or 24 is initialized to num.
- Again at the second run of the while loop, that is, when num holds the value 24, which is again greater than 0, then the program flow again goes inside the while loop and does the same operation as mentioned in the above steps.
- This process continues until the condition of the "while" loop evaluates to false.

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