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In this tutorial, we will learn about how to create a program in C that will ask from user to enter any number as input to find and print sum of even digit and product of odd digit present in that given number.

The question is, *write a program in C to print the sum of even digit and product of odd digit of any given Number from user at
run-time*. Here is the program:

#include<stdio.h> #include<conio.h> int main() { int num, evenSum=0, oddProd=1, rem, temp; printf("Enter any number: "); scanf("%d", &num); while(num>0) { rem = num%10; if(rem%2==0) evenSum = evenSum + rem; else oddProd = oddProd * rem; num = num/10; } printf("\nSum of Even Digit = %d", evenSum); printf("\nProduct of Odd Digit = %d", oddProd); getch(); return 0; }

As the above program was written under **Code::Blocks** IDE, therefore after successful build and run, here is the sample run:

Supply any number say **234879** and press ENTER key to see the **sum of even** digit (that is 2, 4, and 8) and the
**product of odd** digit (that is 3, 7, and 9). As the digit **2**, **4** and **8** are the three even numbers and
**3**, **7** and **9** are the three odd numbers. Therefore the program will calculate the sum of even and product of
odd digit (number). Here is the second snapshot of the sample run:

Here are some of the main steps used in above program:

- Receive any number from user at run-time say
**234879** - Now create a
**while**loop that runs until the number (say**234879**) is greater than 0 - Inside the
**while**loop, initialize**num%10**or**234879%10**or**9**to the variable say**rem**. Here we have calculated the digit (last digit) of the given number by using modulous or remainder operator (%) - Now we have to check that whether the remainder is an even number or an odd number
- If it is an even number, then sum it up
- Here we have used the variable say
**evenSum**to store the summation result of even digit of the given number - Never forgot to initialize 0 to the variable say
**evenSum**at start of the program - If the number is found to be an even number (using
**if**block), just initialize**evenSum+rem**to**evenSum**variable - And if the number is found to be an odd number, then just initialize
**oddProd*rem**to the variable say**oddProd**. Never forgot to initialize 1 to the variable say**oddProd**at start of the program - For example, if user has entered
**234879**as input. Then at first run of the**while**loop,**num%10**or**234879%10**or**9**will be initialized to**rem**. As 9 is an odd number, therefore**oddProd*rem**or**1*9**or**9**will be initialized to**oddProd** - After doing above steps, divide the number with 10, that is initialize
**num/10**or**234879/10**or**23487**to**num** - At second run of the
**while**loop,**num%10**or**23487%10**or**7**will be initialized to**rem**, as 7 is also an odd number, then**oddProd*rem**or**9*7**or**63**will be initialized to**oddProd**, and again divide the number with 10 and continue for the next check - Do the same operation until the number becomes 0
- In this way, after coming out from the
**while**loop, we have two variable say**evenSum**and**oddProd**that holds up the sum of even digit and product of odd digit of the given number say**234879** - Finally print the value of both the variable

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