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# Python Program to Check Armstrong Number

In this article, we've created some programs in Python, to check whether a number entered by user is an Armstrong number or not. Here are the list of programs:

- Simple Program to Check Armstrong Number
- Check Armstrong Number using user-defined Function
- Using class

But before starting these programs, let me clear the thing about Armstrong number, that what it is.

### What is an Armstrong Number ?

A number that equals to the sum of its own digits, where each digit raised to the power of number of digits. For example, 153 is an Armstrong number, because:

153 = 1^{3}+ 5^{3}+ 3^{3}= 1 + 125 + 27 = 153

The result (153) is equal to the number (153) itself. So it is an Armstrong number.

**Note - **Because the total number of digit in 153 is 3, so each of its digit raised to the power of 3.

**Note - **1, 2, 3, 4, 5, 6, 7, 8, and 9 are all Armstrong numbers.

## Check Armstrong Number

To check whether a given number is an Armstrong number or not in Python, you have to ask from user to enter a number, then apply the formula, check and print the message as shown in the program given below:

print("Enter the Number: ") num = int(input()) temp = num noOfDigit = 0 res = 0 while num>0: num = int(num/10) noOfDigit = noOfDigit+1 num = temp while num>0: rem = num%10 pow = 1 i = 0 while i<noOfDigit: pow = pow*rem i = i+1 res = res+pow num = int(num/10) if res==temp: print("\nThe number is an Armstrong Number") else: print("\nThe number is not an Armstrong Number")

Here is the initial output produced by this Python program:

Now supply the input say **1634** and press `ENTER`

key to check whether it is an armstrong number or
not. Here is its sample run with this user input:

Since **1634** is a four-digit number, therefore:

1634 = 1^{4}+ 6^{4}+ 3^{4}+ 4^{4}= 1 + 1296 + 81 + 256 = 1297 + 337 = 1634

In above program, the following block of code:

while num>0: num = int(num/10) noOfDigit = noOfDigit+1

is used to count the total number of digits of given number. The dry run of this block of code with user input **1634** goes like:

- Initial value,
**noOfDigit=0** - The condition,
**num>0**or**1634>0**evaluates to be true, therefore program flow goes to the body of*while loop*and executes both the statements - That is,
**int(num/10)**or**int(1634/10)**or**163**initialized to**num**. So**num=163**now. And**noOfDigit+1**or**0+1**or**1**gets initialized to**noOfDigit**. So**noOfDigit=1** - Now the condition of
*while loop*again gets evaluated, that is the condition**num>0**or**163>0**evaluates to be true again, therefore program flow goes inside its body and executes that two statements again. This process continues, until the condition evaluates to be false - In this way, after exiting from this loop, the variable
**noOfDigit**holds its value as 4

And the following block of code:

while i<noOfDigit: pow = pow*rem i = i+1

is used to calculate the value of digit's raised to the power of number of digit. The dry run of this block of code goes like:

- Initial values,
**i=0**,**noOfDigit=4**,**pow=1**,**rem=4**(because**1634%10**is equal to**4**) - Now the condition
**i<noOfDigit**or**0<4**evaluates to be true, therefore program flow goes inside its body - And
**pow*rem**or**1*4**or**4**gets initialized to**pow**. So**pow=4**, and the value of**i**gets incremented by 1. So**i=1** - Since the condition at second evaluation, that is
**i<noOfDigit**or**1<4**evaluates to be true again, therefore program flow again goes inside the loop and**pow*rem**or**4*4**or**16**initialized to**pow**. So**pow=16**and the value of**i=2** - At third time also, the condition
**i<noOfDigit**or**2<4**evaluates to be true, therefore program flow again goes inside the loop. This process continues until the condition evaluates to be true - In this way, after exiting from this loop, the variable
**pow**holds its value as**1*4*4*4*4**or**256**that is equal to**4**, where 4 is the digit (last digit of number) and power 4 indicates to total number of digit^{4}

After second evaluation of this block of code, **pow** holds its value as **3*3*3*3**, at third time **pow**
holds **6*6*6*6** and at fourth time **pow** holds **1*1*1*1**

#### Modified Version of Previous Program

This is the modified version of previous program. In this program, we've used **end** to skip printing of an
automatic newline using **print()**. And **rem**noOfDigit** is used to find **rem ^{noOfDigit}**
value. The

**str()**method is used to convert any type of value to string type value. Rest of the things are similar to previous program.

print("Enter the Number: ", end="") num = int(input()) temp = num noOfDigit = len(str(num)) res = 0 while num>0: rem = num%10 res = res + (rem ** noOfDigit) num = int(num/10) if res==temp: print("\n" +str(temp)+ " is an Armstrong Number") else: print("\n" +str(temp)+ " is not an Armstrong Number")

Here is its sample run with user input, **9**:

## Check Armstrong Number using Function

This program uses used-defined function named **checkArmstrongNum()** to check whether a number entered by
user at run-time is an Armstrong number or not.

def checkArmstrongNum(x): noOfDigit = 0 res = 0 temp = x while x>0: x = int(x/10) noOfDigit = noOfDigit + 1 x = temp while x>0: rem = x%10 pow = 1 i = 0 while i<noOfDigit: pow = pow * rem i = i + 1 res = res + pow x = int(x/10) if res==temp: return 1 else: return 0 print("Enter the Number: ", end="") num = int(input()) chk = checkArmstrongNum(num) if chk==1: print(num, "is an Armstrong Number") else: print(num, "is not an Armstrong Number")

Here is its sample run with user input, **371**:

Here is another sample run with user input, **532**:

## Check Armstrong Number using Class

This is the last program of this article on checking Armstrong number, using class, an object-oriented feature of Python:

class CodesCracker: def checkArmstrongNum(self, x): noOfDigit = len(str(x)) res = 0 temp = x while x>0: rem = x%10 res = res + (rem ** noOfDigit) x = int(x/10) if res==temp: return 1 else: return 0 print("Enter the Number: ", end="") num = int(input()) obj = CodesCracker() chk = obj.checkArmstrongNum(num) if chk==1: print(num, "is an Armstrong Number") else: print(num, "is not an Armstrong Number")

An object **obj** is created of type **CodesCracker** class to access its member function named **checkArmstrongNum()**
using **dot (.)** operator.

#### Same Program in Other Languages

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