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# Python Program to Calculate Grade of Student

In this article, you will learn and get code in Python to calculate the grades of students. Here is a list of programs for determining a student's grade:

- Calculate the student's grade based on the results of five subjects.
- Based on marks obtained in N number of subjects

The grade must be calculated as per the following rules:

Average Mark | Grade |
---|---|

91-100 | A1 |

81-90 | A2 |

71-80 | B1 |

61-70 | B2 |

51-60 | C1 |

41-50 | C2 |

33-40 | D |

21-32 | E1 |

0-20 | E2 |

## Calculate the Grade of the Student in Python

This program finds and prints the grade of a student based on marks obtained in five subjects entered by the user at run-time.

To calculate the grade of students in Python, you have to ask the user to enter marks obtained in five subjects. Now calculate the sum of all the marks and then calculate the average marks to find the grade according to the average marks obtained by the student, as shown in the program given below:

The following Python program asks the user to enter marks obtained in five subjects to calculate and print the student's grade:

print("Enter Marks Obtained in 5 Subjects: ") markOne = int(input()) markTwo = int(input()) markThree = int(input()) markFour = int(input()) markFive = int(input()) tot = markOne+markTwo+markThree+markFour+markFive avg = tot/5 if avg>=91 and avg<=100: print("Your Grade is A1") elif avg>=81 and avg<91: print("Your Grade is A2") elif avg>=71 and avg<81: print("Your Grade is B1") elif avg>=61 and avg<71: print("Your Grade is B2") elif avg>=51 and avg<61: print("Your Grade is C1") elif avg>=41 and avg<51: print("Your Grade is C2") elif avg>=33 and avg<41: print("Your Grade is D") elif avg>=21 and avg<33: print("Your Grade is E1") elif avg>=0 and avg<21: print("Your Grade is E2") else: print("Invalid Input!")

Here are some sample runs of the above Python program to demonstrate how to calculate the grade of a student.

When you run the above code, you will see the following sample output, which asks the user to enter marks obtained in 5 subjects:

Now enter the marks obtained in 5 subjects, say 89, 99, 98, 92, and 77, and then press the ENTER key to see the grade obtained according to the marks entered, as shown in the snapshot given below:

**Note**: If mark contains decimal values like 98.6, 86.9, etc., then replace int with float.

That is, to handle floating-point (values containing decimal) values, replace the following block of code:

markOne = int(input()) markTwo = int(input()) markThree = int(input()) markFour = int(input()) markFive = int(input())

with the block of code given below:

markOne = float(input()) markTwo = float(input()) markThree = float(input()) markFour = float(input()) markFive = float(input())

### Receive marks using Loop and Find Grade

This programme uses a loop to receive marks obtained in five subjects. It also uses a loop to find the total mark:

mark = [] tot = 0 print("Enter Marks Obtained in 5 Subjects: ") for i in range(5): mark.insert(i, input()) for i in range(5): tot = tot + int(mark[i]) avg = tot/5 if avg>=91 and avg<=100: print("Your Grade is A1") elif avg>=81 and avg<91: print("Your Grade is A2") elif avg>=71 and avg<81: print("Your Grade is B1") elif avg>=61 and avg<71: print("Your Grade is B2") elif avg>=51 and avg<61: print("Your Grade is C1") elif avg>=41 and avg<51: print("Your Grade is C2") elif avg>=33 and avg<41: print("Your Grade is D") elif avg>=21 and avg<33: print("Your Grade is E1") elif avg>=0 and avg<21: print("Your Grade is E2") else: print("Invalid Input!")

Here is its sample run with user input: 89, 76, 78, 45, and 35 as marks obtained in 5 subjects:

**Note**: You can also use append() in place of insert(). To do so, just replace the following statement:

mark.insert(i, input())

with the statement given below:

mark.append(input())

The following block of code (from the above program):

for i in range(5): mark.insert(i, input())

is created to execute the following statement:

mark.insert(i, input())

five times from 0 to 4. That is, this statement gets executed five times with the value of i ranging from 0 to 4.

When i's value is 0 (at first execution), then the mark entered by the user gets stored in the list at mark[0]. Now, the value of i is 1, so the mark entered by the user is stored in the list at mark[1], and so on up to five times.

### Obtain Marks for N Subjects and Determine Grade

This program allows the user to enter the number of subjects along with the marks obtained in all subjects. That is, this program finds and prints the grade of a student based on the marks obtained in N subjects. The value of N and marks in N subjects must be entered by the user:

mark = [] tot = 0 print("Enter Number of Subjects: ") subNo = int(input()) print("Enter Marks Obtained in " + str(subNo) + " Subjects: ") for i in range(subNo): mark.append(input()) for i in range(subNo): tot = tot + int(mark[i]) avg = tot/subNo if avg>=91 and avg<=100: print("Grade = A1") elif avg>=81 and avg<91: print("Grade = A2") elif avg>=71 and avg<81: print("Grade = B1") elif avg>=61 and avg<71: print("Grade = B2") elif avg>=51 and avg<61: print("Grade = C1") elif avg>=41 and avg<51: print("Grade = C2") elif avg>=33 and avg<41: print("Grade = D") elif avg>=21 and avg<33: print("Grade = E1") elif avg>=0 and avg<21: print("Grade = E2") else: print("Invalid Input!")

Here is its sample run with user input, 6 as the number of subjects, and 56, 46, 76, 87, 45, and 37 as the marks obtained in the 6 subjects:

Here is another sample run with user input, 10 as the total number of subjects, and 56, 76, 87, 90, 45, 44, 34, 56, 76, and 80 as the marks obtained in the 10 subjects:

#### Same Program in Other Languages

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