Check Armstrong or Not in C++
To check whether a number is an Armstrong number or not an Armstrong number in
C++ programming, you have to ask to the user to enter the number
(any positive number), now check for the Armstrong number i.e., whether the entered/given number is an Armstrong number or not.
To check whether any positive number is an Armstrong number or not, following is the example:
- Since 153 is equal to 1*1*1 + 5*5*5 + 3*3*3. So 153 is an Armstrong number
- Since 12 is not equal to 1*1*1 + 2*2*2. So 12 is not an Armstrong number
After checking for the Armstrong number, print the result on the output screen as shown here in the following program.
C++ Programming Code to Check Armstrong or Not
Following C++ program ask to the user to enter any positive integer to find whether it is an Armstrong number or not, then
display the result on the screen:
/* C++ Program - Check Armstrong or Not */
#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int n, nu, num=0, rem;
cout<<"Enter any positive number : ";
cin>>n;
nu=n;
while(nu!=0)
{
rem=nu%10;
num=num + rem*rem*rem;
nu=nu/10;
}
if(num==n)
{
cout<<"Armstrong Number";
}
else
{
cout<<"Not Armstrong Number";
}
getch();
}
When the above C++ program is compile and executed, it will produce the following result.
Above C++ Programming Example Output (for Armstrong number):
Above C++ Programming Example Output (for not Armstrong number):
Same Program in Other Language
You may like the same program in other programming languages:
C++ Programming Online Test
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