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# Python Program to Convert Octal to Binary

In this article, I've created some programs in Python, to convert octal number entered by user to its equivalent binary value. Here are the list of programs:

- Octal to Binary using
**while Loop** - Using
**int()**and**bin()**Methods - Using
**Function** - Using
**Class**

**Note - **Before creating these programs, if you're not aware about steps used for the conversion, then refer
to Octal to Binary Formula and Example to get every required things.

## Octal to Binary using while Loop

To convert octal to binary number in Python, you have to ask from user to enter any octal number, then convert that number into its
binary equivalent. The question is, **write a Python program to convert octal number to binary using while loop**. Here is its answer:

print("Enter the Octal Number: ") octnum = int(input()) rev = 0 chk = 0 while octnum!=0: rem = octnum%10 if rem>7: chk = 1 break rev = rem + (rev*10) octnum = int(octnum/10) if chk == 0: octnum = rev binnum = "" while octnum!=0: rem = octnum%10 if rem==0: binnum = binnum + "000" elif rem==1: binnum = binnum + "001" elif rem==2: binnum = binnum + "010" elif rem==3: binnum = binnum + "011" elif rem==4: binnum = binnum + "100" elif rem==5: binnum = binnum + "101" elif rem==6: binnum = binnum + "110" elif rem==7: binnum = binnum + "111" octnum = int(octnum/10) print("\nEquivalent Binary Value = ", binnum) else: print("\nInvalid Input!")

Here is its sample run:

Now supply the input say **723** as octal number and press `ENTER`

key to convert and print its
equivalent binary value as shown in the snapshot given below:

The dry run of above program with user input **723** goes like:

- Initial values,
**octnum=723**(entered by user),**rev=0**,**chk=0** - Now the condition (of
**while loop**)**octnum!=0**or**723!=0**evaluates to be true, therefore program flow goes inside the loop. This loop is created to reverse the entered octal number. Because, we've to convert binary equivalent of each and every digit. But using**rem = octnum%10**statement, the digit we get is the last digit at first time. Therefore we've reversed the number before conversion - Inside the loop,
**octnum%10**or**723%10**or**3**gets initialized to**rem**. So**rem=3** - Now the condition (of
**if**)**rem>7**or**3>7**evaluates to be false, therefore the program flow does not goes inside this**if**'s body. Here we've checked whether any digit is greater than 7 or not. Because 8, 9 are both invalid octal digits - Now
**rem + (rev*10)**or**3 + (0*10)**or**3**gets initialized to**rev** **int(octnum/10)**or**int(723/10)**or**72**gets initialized to**octnum**- Program flow goes back and evaluates the condition of
**while loop**again with new value of**octnum**. - That is, the condition
**octnum!=0**or**72!=0**evaluates to be true again, therefore program flow again goes inside the loop. This process continues until the condition evaluates to be false - In this way, after exiting from the loop when its condition evaluates to be false, the variable
**rev**holds its value as**327**. Therefore**rev=327** - Now the condition
**chk==0**or**0==0**evaluates to be true, therefore program flow goes inside the loop **rev**or**327**gets initialized to**octnum**. And**""**gets initialized to**binnum**. That is, a string variable**binnum**with empty content gets defined- Now the condition (of inner
**while loop**)**octnum!=0**or**327!=0**evaluates to be true, therefore program flow goes inside the loop - And
**octnum%10**or**327%10**or**7**gets initialized to**rem** - Since the value of
**rem**is 7, therefore the condition of last**elif**, that is**rem==7**or**7==7**evaluates to be true, therefore**binnum + "111"**or**"" + "111"**or**"111"**gets initialized to**binnum** - Then
**int(octnum/10)**or**int(327/10**or**32**gets initialized to**octnum** - Now program flow goes back and evaluates the condition of
**while loop**(inner) again - That is, the condition
**octnum!=0**or**32!=0**evaluates to be true again, therefore program flow goes inside the loop again. This process continues until the condition evaluates to be false - In this way, the given octal value gets converted into its equivalent binary value
- Now print the value of
**binnum**after exiting from the loop

## Octal to Binary using int() and bin()

This program uses **int()** and **bin()**, predefined methods of Python to do the same job as of previous program
creating using complete user-defined code. The **int()** is used to convert a value passed as its argument to its
integer equivalent. Whereas **bin()** returns binary equivalent of value passed as its argument.

print("Enter Octal Number: ", end="") onum = input() bnum = int(onum, 8) bnum = bin(bnum) print("\nEquivalent Binary Value =", bnum)

Here is its sample run with user input **324**:

**Note - **To skip first two characters, add **[2:]** just after **bnum** while printing. That is, replace the following statement:

print("\nEquivalent Binary Value =", bnum)

with the statement given below:

print("\nEquivalent Binary Value =", bnum[2:])

Now the output looks like, with same user input as of previous sample run:

**Note - **The **end=** is used to skip printing of an automatic newline using **print()**

## Octal to Binary using Function

This program uses user-defined function named **OctToBin()** to convert octal to binary. The function takes
a number (octal) as its argument and returns its equivalent binary value using **int()** and **bin()**:

def OctToBin(o): return bin(int(o, 8)) print("Enter Octal Number: ", end="") onum = input() bnum = OctToBin(onum) print("\nEquivalent Binary Value =", bnum[2:])

## Octal to Binary using Class

This is the last program of this article, created using a class named **CodesCracker**. Class is an object-oriented feature of Python.

class CodesCracker: def OctToBin(self, o): return bin(int(o, 8)) print("Enter Octal Number: ", end="") onum = input() obj = CodesCracker() bnum = obj.OctToBin(onum) print("\nEquivalent Binary Value =", bnum[2:])

An object **obj** of class **CodesCracker** is created to access its member function, **OctToBin()** using **dot (.)** operator.

#### Same Program in Other Languages

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