C++ Program to Find and Print Odd Numbers in an Array

This article provides some programs in C++ that find and print all odd numbers in an array entered by the user. The list of programs covered here is as follows:

Print odd numbers in an array of 10 elements

The question is, "Write a C++ program that receives 10 elements (numbers) from the user at run-time and prints all odd numbers." The program given below is its answer:

#include<iostream>

using namespace std;
int main()
{
   int arr[10], i;
   cout<<"Enter 10 numbers: ";
   for(i=0; i<10; i++)
      cin>>arr[i];
   cout<<"\nList of Odd Numbers are:\n";
   for(i=0; i<10; i++)
   {
      if(arr[i]%2!=0)
         cout<<arr[i]<<" ";
   }
   cout<<endl;
   return 0;
}

The snapshot given below shows the initial output produced by the above C++ program on printing all the odd numbers available in a given array:

c++ print odd numbers in array

Enter any 10 numbers, such as 21, 22, 23, 24, 25, 26, 27, 28, 29, and 30, and press ENTER key to find and print all odd numbers from these ten numbers, as shown in the screenshot below:

print odd numbers in array c++

Print odd numbers in an array of n elements

This program lets the user enter both the size (n) and the array elements.

#include<iostream>

using namespace std;
int main()
{
   int n, i;
   cout<<"Enter the value of n: ";
   cin>>n;
   int arr[n];
   cout<<"Enter any "<<n<<" numbers: ";
   for(i=0; i<n; i++)
      cin>>arr[i];
   cout<<"\nList of Odd Numbers:\n";
   for(i=0; i<n; i++)
   {
      if(arr[i]%2!=0)
         cout<<arr[i]<<" ";
   }
   cout<<endl;
   return 0;
}

Here is its sample run with user input of 5 as size and 100, 101, 102, 103, and 104 as the five elements or numbers for the array:

c++ program find odd numbers in array

Find and Print Odd Numbers Using Another Array

This program uses two arrays: one stores the original array, and the second stores only odd numbers from the original array.

#include<iostream>

using namespace std;
int main()
{
   int n, i, j=0;
   cout<<"Enter the value of n: ";
   cin>>n;
   int arr[n], odd[n];
   cout<<"Enter any "<<n<<" numbers: ";
   for(i=0; i<n; i++)
   {
      cin>>arr[i];
      if(arr[i]%2!=0)
      {
         odd[j] = arr[i];
         j++;
      }
   }
   if(j==0)
      cout<<"\nOdd number not found in the array!";
   else if(j==1)
      cout<<"\nOnly one odd number found. That is:\n"<<odd[0];
   else
   {
      cout<<"\nList of Odd numbers:\n";
      for(i=0; i<j; i++)
         cout<<odd[i]<<" ";
   }
   cout<<endl;
   return 0;
}

Here is its sample run with user input of 4 as size and 100, 102, 103, 104 as four elements or numbers:

c++ find odd numbers in array

C++ Quiz


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