Count Positive, Negative and Zero in C++
To count the number of positive number, negative number, and zero from the given set of
numbers entered by the user in C++ programming, you have to ask
to the user to enter some set of numbers (10 numbers here). Now to find occurrence of positive, negative and zero from the given
set of numbers, just check all the numbers using for loop whether the number is 0,
less than zero or greater than 0 to count the occurrence of positive, negative and zero as shown here in the following program.
C++ Programming Code to Count Occurrence of Positive, Zero and Negative Numbers
Following C++ program ask to the user to enter 10 numbers to check for number of positive number, negative number and
zero occurrence, then display the result on the screen:
/* C++ Program - Count Occurrence of Numbers */
#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int countp=0, countn=0, countz=0, arr[10], i;
cout<<"Enter 10 numbers : ";
for(i=0; i<10; i++)
{
cin>>arr[i];
}
for(i=0; i<10; i++)
{
if(arr[i]<0)
{
countn++;
}
else if(arr[i]==0)
{
countz++;
}
else
{
countp++;
}
}
cout<<"Positive Numbers = "<<countp<<"\n";
cout<<"Negative Numbers = "<<countn<<"\n";
cout<<"Zero = "<<countz<<"\n";
getch();
}
When the above C++ program is compile and executed, it will produce the following result:
Same Program in Other Language
You may like the same program in other programming languages:
C++ Programming Online Test
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