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C++ Program to Find and Print Sum of First n Natural Numbers
This article is created to provide some programs in C++ that find and prints the sum of first n natural numbers. The value n must be entered by user at run-time. The program is created in following ways:
- Using while loop
- Using for loop
- Using user-defined function
Note - Natural number starts with 1 and continues like 1, 2, 3, ....
Find Sum of First n Natural Numbers using while Loop
The question is, write a program in C++ that receives the value of n and print the sum of first n natural numbers. Here is its answer:
#include<iostream> using namespace std; int main() { int n, natural=1, sum=0; cout<<"Enter the Value of n: "; cin>>n; while(natural<=n) { sum = sum+natural; natural++; } cout<<"\nSum of First "<<n<<" Natural Numbers = "<<sum; cout<<endl; return 0; }
Here is the initial output produced by above C++ program on finding and printing the sum of n natural numbers:
Now supply the number say 10 as the value of n and press ENTER
key to find sum of first 10 natural
numbers like shown in the snapshot given below:
Find Sum of First n Natural Numbers using for Loop
This program is created using for loop, instead of while.
#include<iostream> using namespace std; int main() { int n, natural, sum=0; cout<<"Enter the Value of n: "; cin>>n; for(natural=1; natural<=n; natural++) sum = sum+natural; cout<<"\nSum of First "<<n<<" Natural Numbers = "<<sum; cout<<endl; return 0; }
Here is its sample run with user input 12:
Find Sum of First n Natural Numbers using Function
This is the last program created using a user-defined function named myfun() that takes an integer say n as its argument, then find and return the sum of first n natural numbers.
#include<iostream> using namespace std; int myfun(int); int main() { int n, sum; cout<<"Enter the Value of n: "; cin>>n; sum = myfun(n); cout<<"\nSum of First "<<n<<" Natural Numbers = "<<sum; cout<<endl; return 0; } int myfun(int n) { int natural, sum=0; for(natural=1; natural<=n; natural++) sum += natural; return sum; }
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