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Java Program to Find Smallest Number in an Array
This article is created to cover a program in Java that find and prints the smallest number in an array of n numbers or elements, entered by user at run-time.
Java Find Smallest Number in Array using for Loop
The question is, write a Java program to find the smallest number in an array of n numbers. The program given below is its answer:
import java.util.Scanner; public class CodesCracker { public static void main(String[] args) { int tot, i, small; Scanner scan = new Scanner(System.in); System.out.print("Enter the Size of Array: "); tot = scan.nextInt(); int[] arr = new int[tot]; System.out.print("Enter " +tot+ " Numbers: "); for(i=0; i<tot; i++) arr[i] = scan.nextInt(); small = arr[0]; for(i=1; i<tot; i++) { if(small>arr[i]) small = arr[i]; } System.out.println("\nSmallest Number = " +small); } }
The snapshot given below shows the sample run of above program with user input 6 as size and 20, 21, 22, 17, 18, 19 as six numbers, to find and print the smallest number among these:
Java Find Smallest Number in Array using while Loop
To create the same program using while loop, instead of for. Then replace the following block of code, from above program:
for(i=1; i<tot; i++) { if(small>arr[i]) small = arr[i]; }
with the block of code given below:
i = 0; while(i<tot) { if(small>arr[i]) small = arr[i]; i++; }
Same Program in Other Languages
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